3 条题解
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0
解析:找出每个字符串中最大的字符,根据其大小判断可能是几进制数,详见代码:
#include <iostream> using namespace std; int main() { int n = 0; cin >> n; for (int i = 0; i < n; i++) { string s; cin >> s; char maxc = '0'; for (int i = 0; i<s.length(); i++) if (s[i] > maxc) maxc = s[i]; if (maxc>'F'){ cout<<"0 0 0 0"<<endl; }else if(maxc>'9'){ cout<<"0 0 0 1"<<endl; }else if (maxc>'7'){ cout<<"0 0 1 1"<<endl; }else if (maxc>'1'){ cout<<"0 1 1 1"<<endl; }else{ cout<<"1 1 1 1"<<endl; } } return 0; }
另一种解法:
#include <iostream> using namespace std; int main() { int n = 0; cin >> n; for (int i = 0; i < n; i++) { char str[11]; cin >> str; char max = '0'; for (int i = 0; str[i] != '\0'; i++) if (str[i] > max) max = str[i]; cout << (max <= '1') << " " << (max <= '7') << " " << (max <= '9') << " " << (max <= 'F') << endl; } return 0; }
信息
- ID
- 1298
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 7
- 已通过
- 2
- 上传者